Author Topic: creating an array of numbers  (Read 5429 times)

Offline muratohyes

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creating an array of numbers
« on: July 01, 2014, 11:03:11 AM »
I'm trying to populate an array of "string"s. These include only 1..9 as digits and each digit in a number should be different. The number of digits is taken from the user.
As the digits will be non-zero and different, I wrote some code to determine the starting point and ending point of the numbers. e.g 4 digits start from 1234 to 9876.

My algorithm on solving the issue is like following:

      from i =1234 to 9876
             if: all the chars are different and non-zero in the current number
                    s = convert.tostring(i)
                    add.tolist(s)

So I need a data structure/method like linked list. How should I act in such a situation? Any code or algorithm would be great. I especially need help on allocation of and adding a new element to the list.

Offline Frank Kotler

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Re: creating an array of numbers
« Reply #1 on: July 02, 2014, 04:27:04 AM »
Hi Muratohyes,

It isn't clear what you propose to do with this list once you've got it, which might make a difference. Perhaps something like...
Code: [Select]
struc listnode
    .pnext resq 1
    .pstr resq 1
; .pprev resq 1 :?
endstruc

section .bss
    listhead resq 1

section .text
; ...

addnode:
; ummm parameters listhead and pointer to string?
; returns... address of new node? or just success (or not)

; traverse to current end of list
; (listnode + listnode.pnext = 0)
; move it to... say... rbx?

mov rdi, listnode_size
call malloc ; yours or library?
mov [rbx + listnode.pnext], rax
mov [rax + listnode.pnext], 0
mov [rax + listnode.pstr], rsi ; passed in parameter
ret ;? are we done?
That obviously isn't intended to run, but "something like that"? If I haven't screwed it up too badly?

You haven't given us much of a clue what we're up against. What OS? What bitness? What parts can you do? Where do you get stuck? The more you give us, the more we can/will give you!

Best,
Frank