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line continuation
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Topic: line continuation (Read 17495 times)
nobody
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line continuation
«
on:
January 10, 2006, 06:01:17 PM »
The documentation that I have says that backslash(\) is the line continuation character.
I would assume that if that is the case then I should be able to do the following:
mov eax, \
prompt1
But I get an expression syntax error!
Any suggestions?
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Frank Kotler
NASM Developer
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Posts: 2667
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Re: line continuation
«
Reply #1 on:
January 10, 2006, 06:37:54 PM »
Works fine for me. Is the '\' the *very* last thing on the line? Spaces or tabs after it won't work.
Best,
Frank
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nobody
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Re: line continuation
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Reply #2 on:
January 10, 2006, 06:39:05 PM »
Ensure that the backslash is the last
character on its line, i.e. that it is
not followed by whitespaces or tabs.
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nobody
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Re: line continuation
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Reply #3 on:
January 10, 2006, 06:57:54 PM »
It is the last thing on the line not counting the newline character.
I am running on Linux use ELF with i686 architecture. Other suggestions?
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